53040133331 has 8 divisors (see below), whose sum is σ = 56167693344. Its totient is φ = 49913412480.

The previous prime is 53040133309. The next prime is 53040133357. The reversal of 53040133331 is 13333104035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53040133331 - 2³⁴ = 35860264147 is a prime.

It is a super-2 number, since 2×53040133331² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53040133331.

It is not an unprimeable number, because it can be changed into a prime (53040133631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 77255 + ... + 334736.

It is an arithmetic number, because the mean of its divisors is an integer number (7020961668).

Almost surely, 2^53040133331 is an apocalyptic number.

53040133331 is a deficient number, since it is larger than the sum of its proper divisors (3127560013).

53040133331 is a wasteful number, since it uses less digits than its factorization.

53040133331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 419581.

The product of its (nonzero) digits is 4860, while the sum is 26.

Adding to 53040133331 its reverse (13333104035), we get a palindrome (66373237366).

The spelling of 53040133331 in words is "fifty-three billion, forty million, one hundred thirty-three thousand, three hundred thirty-one".