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5304023113353 = 317284033661601
BaseRepresentation
bin100110100101111000001…
…1010011101111010001001
3200210001121111020111011120
41031023300122131322021
51143400114404111403
615140345022545453
71055126431405116
oct115136032357211
920701544214146
105304023113353
111765472854428
12717b56738289
132c6223547b03
14144a04d3790d
1592e831bde53
hex4d2f069de89

5304023113353 has 16 divisors (see below), whose sum is σ = 7488298310976. Its totient is φ = 3327896422400.

The previous prime is 5304023113331. The next prime is 5304023113379. The reversal of 5304023113353 is 3533113204035.

It is a cyclic number.

It is not a de Polignac number, because 5304023113353 - 26 = 5304023113289 is a prime.

It is a super-2 number, since 2×53040231133532 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5304023115353) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 382248 + ... + 3279353.

It is an arithmetic number, because the mean of its divisors is an integer number (468018644436).

Almost surely, 25304023113353 is an apocalyptic number.

It is an amenable number.

5304023113353 is a deficient number, since it is larger than the sum of its proper divisors (2184275197623).

5304023113353 is a wasteful number, since it uses less digits than its factorization.

5304023113353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3690024.

The product of its (nonzero) digits is 48600, while the sum is 33.

Adding to 5304023113353 its reverse (3533113204035), we get a palindrome (8837136317388).

The spelling of 5304023113353 in words is "five trillion, three hundred four billion, twenty-three million, one hundred thirteen thousand, three hundred fifty-three".

Divisors: 1 3 17 51 28403 85209 482851 1448553 3661601 10984803 62247217 186741651 104000453203 312001359609 1768007704451 5304023113353