53040433 has 4 divisors (see below), whose sum is σ = 53201008. Its totient is φ = 52879860.

The previous prime is 53040397. The next prime is 53040443. The reversal of 53040433 is 33404035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53040433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53040443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79791 + ... + 80452.

It is an arithmetic number, because the mean of its divisors is an integer number (13300252).

Almost surely, 2^53040433 is an apocalyptic number.

It is an amenable number.

53040433 is a deficient number, since it is larger than the sum of its proper divisors (160575).

53040433 is a wasteful number, since it uses less digits than its factorization.

53040433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 160574.

The product of its (nonzero) digits is 2160, while the sum is 22.

The square root of 53040433 is about 7282.8863096989. The cubic root of 53040433 is about 375.7240718349.

Adding to 53040433 its reverse (33404035), we get a palindrome (86444468).

The spelling of 53040433 in words is "fifty-three million, forty thousand, four hundred thirty-three".