Base | Representation |
---|---|
bin | 1111011100000000100… |
… | …10001011001011100001 |
3 | 1212201010210200202012100 |
4 | 13232000102023023201 |
5 | 32142311401203231 |
6 | 1043402212521013 |
7 | 53215426011210 |
oct | 7560022131341 |
9 | 1781123622170 |
10 | 530433225441 |
11 | 194a56800189 |
12 | 86975020169 |
13 | 3b0341b8592 |
14 | 1b95d001077 |
15 | dbe77d51e6 |
hex | 7b8048b2e1 |
530433225441 has 12 divisors (see below), whose sum is σ = 875635800832. Its totient is φ = 303104700216.
The previous prime is 530433225437. The next prime is 530433225481. The reversal of 530433225441 is 144522334035.
530433225441 is a `hidden beast` number, since 5 + 30 + 4 + 332 + 254 + 41 = 666.
It is not a de Polignac number, because 530433225441 - 22 = 530433225437 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 530433225396 and 530433225405.
It is not an unprimeable number, because it can be changed into a prime (530433225481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4209787441 + ... + 4209787566.
Almost surely, 2530433225441 is an apocalyptic number.
It is an amenable number.
530433225441 is a deficient number, since it is larger than the sum of its proper divisors (345202575391).
530433225441 is a wasteful number, since it uses less digits than its factorization.
530433225441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8419575020 (or 8419575017 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 36.
Adding to 530433225441 its reverse (144522334035), we get a palindrome (674955559476).
The spelling of 530433225441 in words is "five hundred thirty billion, four hundred thirty-three million, two hundred twenty-five thousand, four hundred forty-one".
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