Base | Representation |
---|---|
bin | 100110100110000100000… |
… | …1101110000010101100001 |
3 | 200210002122022122002022112 |
4 | 1031030020031300111201 |
5 | 1143401424120343040 |
6 | 15140452405445105 |
7 | 1055142350520512 |
oct | 115141015602541 |
9 | 20702568562275 |
10 | 5304422434145 |
11 | 17656581a600a |
12 | 718048410795 |
13 | 2c62881ac1c3 |
14 | 144a41da2a09 |
15 | 92ea829b365 |
hex | 4d308370561 |
5304422434145 has 8 divisors (see below), whose sum is σ = 6365413402920. Its totient is φ = 4243466959360.
The previous prime is 5304422434127. The next prime is 5304422434153. The reversal of 5304422434145 is 5414342244035.
It can be written as a sum of positive squares in 4 ways, for example, as 362017619041 + 4942404815104 = 601679^2 + 2223152^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5304422434145 - 212 = 5304422430049 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8543600 + ... + 9143409.
It is an arithmetic number, because the mean of its divisors is an integer number (795676675365).
Almost surely, 25304422434145 is an apocalyptic number.
It is an amenable number.
5304422434145 is a deficient number, since it is larger than the sum of its proper divisors (1060990968775).
5304422434145 is a wasteful number, since it uses less digits than its factorization.
5304422434145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17746995.
The product of its (nonzero) digits is 921600, while the sum is 41.
The spelling of 5304422434145 in words is "five trillion, three hundred four billion, four hundred twenty-two million, four hundred thirty-four thousand, one hundred forty-five".
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