Base | Representation |
---|---|
bin | 100110100110000100010… |
… | …1110011111010100100011 |
3 | 200210002122220210001022111 |
4 | 1031030020232133110203 |
5 | 1143401433314441303 |
6 | 15140453313420151 |
7 | 1055142513460255 |
oct | 115141056372443 |
9 | 20702586701274 |
10 | 5304431015203 |
11 | 17656620270a1 |
12 | 71804b26a657 |
13 | 2c6289bc4c58 |
14 | 144a43197cd5 |
15 | 92ea8de3b6d |
hex | 4d308b9f523 |
5304431015203 has 4 divisors (see below), whose sum is σ = 5310606139480. Its totient is φ = 5298255890928.
The previous prime is 5304431015197. The next prime is 5304431015227. The reversal of 5304431015203 is 3025101344035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5304431015203 - 25 = 5304431015171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5304431015803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3087560850 + ... + 3087562567.
It is an arithmetic number, because the mean of its divisors is an integer number (1327651534870).
Almost surely, 25304431015203 is an apocalyptic number.
5304431015203 is a deficient number, since it is larger than the sum of its proper divisors (6175124277).
5304431015203 is an equidigital number, since it uses as much as digits as its factorization.
5304431015203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6175124276.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5304431015203 its reverse (3025101344035), we get a palindrome (8329532359238).
The spelling of 5304431015203 in words is "five trillion, three hundred four billion, four hundred thirty-one million, fifteen thousand, two hundred three".
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