Base | Representation |
---|---|
bin | 110001011001101100… |
… | …111000110010010001 |
3 | 12001220202200011112221 |
4 | 301121230320302101 |
5 | 1332113400443310 |
6 | 40211320421041 |
7 | 3555331131133 |
oct | 613154706221 |
9 | 161822604487 |
10 | 53044546705 |
11 | 2055029a057 |
12 | a344617781 |
13 | 5004750457 |
14 | 27d2c11053 |
15 | 15a6cd7ada |
hex | c59b38c91 |
53044546705 has 4 divisors (see below), whose sum is σ = 63653456052. Its totient is φ = 42435637360.
The previous prime is 53044546691. The next prime is 53044546747. The reversal of 53044546705 is 50764544035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 23251370256 + 29793176449 = 152484^2 + 172607^2 .
It is not a de Polignac number, because 53044546705 - 25 = 53044546673 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5304454666 + ... + 5304454675.
It is an arithmetic number, because the mean of its divisors is an integer number (15913364013).
Almost surely, 253044546705 is an apocalyptic number.
It is an amenable number.
53044546705 is a deficient number, since it is larger than the sum of its proper divisors (10608909347).
53044546705 is a wasteful number, since it uses less digits than its factorization.
53044546705 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10608909346.
The product of its (nonzero) digits is 1008000, while the sum is 43.
The spelling of 53044546705 in words is "fifty-three billion, forty-four million, five hundred forty-six thousand, seven hundred five".
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