Base | Representation |
---|---|
bin | 100110100110000111011… |
… | …0100011011011000110011 |
3 | 200210002221001010100212012 |
4 | 1031030032310123120303 |
5 | 1143402141002012001 |
6 | 15140511404353135 |
7 | 1055145164360015 |
oct | 115141664333063 |
9 | 20702831110765 |
10 | 5304533235251 |
11 | 17657047a4578 |
12 | 7180795457ab |
13 | 2c62a51350a3 |
14 | 144a529a61b5 |
15 | 92eb2d862bb |
hex | 4d30ed1b633 |
5304533235251 has 4 divisors (see below), whose sum is σ = 5308374317904. Its totient is φ = 5300692152600.
The previous prime is 5304533235241. The next prime is 5304533235271. The reversal of 5304533235251 is 1525323354035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5304533235251 - 26 = 5304533235187 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5304533235199 and 5304533235208.
It is not an unprimeable number, because it can be changed into a prime (5304533235241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1920539255 + ... + 1920542016.
It is an arithmetic number, because the mean of its divisors is an integer number (1327093579476).
Almost surely, 25304533235251 is an apocalyptic number.
5304533235251 is a deficient number, since it is larger than the sum of its proper divisors (3841082653).
5304533235251 is a wasteful number, since it uses less digits than its factorization.
5304533235251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3841082652.
The product of its (nonzero) digits is 810000, while the sum is 41.
Adding to 5304533235251 its reverse (1525323354035), we get a palindrome (6829856589286).
The spelling of 5304533235251 in words is "five trillion, three hundred four billion, five hundred thirty-three million, two hundred thirty-five thousand, two hundred fifty-one".
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