Base | Representation |
---|---|
bin | 100110100110010001101… |
… | …0001001111011011011001 |
3 | 200210010210221201112011101 |
4 | 1031030203101033123121 |
5 | 1143403341320122021 |
6 | 15141005422231401 |
7 | 1055156531555215 |
oct | 115144321173331 |
9 | 20703727645141 |
10 | 5304876332761 |
11 | 1765870434835 |
12 | 718154425561 |
13 | 2c632b242575 |
14 | 144a86397945 |
15 | 92ed3059a91 |
hex | 4d32344f6d9 |
5304876332761 has 4 divisors (see below), whose sum is σ = 5304897259024. Its totient is φ = 5304855406500.
The previous prime is 5304876332741. The next prime is 5304876332897. The reversal of 5304876332761 is 1672336784035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5304876332761 - 235 = 5270516594393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5304876332741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10078155 + ... + 10591456.
It is an arithmetic number, because the mean of its divisors is an integer number (1326224314756).
Almost surely, 25304876332761 is an apocalyptic number.
It is an amenable number.
5304876332761 is a deficient number, since it is larger than the sum of its proper divisors (20926263).
5304876332761 is a wasteful number, since it uses less digits than its factorization.
5304876332761 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20926262.
The product of its (nonzero) digits is 15240960, while the sum is 55.
The spelling of 5304876332761 in words is "five trillion, three hundred four billion, eight hundred seventy-six million, three hundred thirty-two thousand, seven hundred sixty-one".
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