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5305000011 = 31768333337
BaseRepresentation
bin1001111000011001…
…11110000001001011
3111200201021220220220
410330030332001023
541331040000021
62234224321123
7245314520223
oct47414760113
914621256826
105305000011
112282597033
1210407731a3
136670ba47c
143847b7083
15210b01cc6
hex13c33e04b

5305000011 has 4 divisors (see below), whose sum is σ = 7073333352. Its totient is φ = 3536666672.

The previous prime is 5304999907. The next prime is 5305000033. The reversal of 5305000011 is 1100005035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5305000011 - 27 = 5304999883 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5305000061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 884166666 + ... + 884166671.

It is an arithmetic number, because the mean of its divisors is an integer number (1768333338).

Almost surely, 25305000011 is an apocalyptic number.

5305000011 is a deficient number, since it is larger than the sum of its proper divisors (1768333341).

5305000011 is a wasteful number, since it uses less digits than its factorization.

5305000011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1768333340.

The product of its (nonzero) digits is 75, while the sum is 15.

The square root of 5305000011 is about 72835.4310140333. The cubic root of 5305000011 is about 1744.0615048020.

Adding to 5305000011 its reverse (1100005035), we get a palindrome (6405005046).

The spelling of 5305000011 in words is "five billion, three hundred five million, eleven", and thus it is an aban number.

Divisors: 1 3 1768333337 5305000011