Base | Representation |
---|---|
bin | 1111011100001001000… |
… | …00111110011100101001 |
3 | 1212201022202021100121211 |
4 | 13232010200332130221 |
5 | 32142433034324223 |
6 | 1043413230233121 |
7 | 53220250263643 |
oct | 7560440763451 |
9 | 1781282240554 |
10 | 530504214313 |
11 | 194a92887177 |
12 | 869949557a1 |
13 | 3b045b12228 |
14 | 1b9685dd893 |
15 | dbedb58d0d |
hex | 7b8483e729 |
530504214313 has 8 divisors (see below), whose sum is σ = 532443724488. Its totient is φ = 528564879744.
The previous prime is 530504214311. The next prime is 530504214347. The reversal of 530504214313 is 313412405035.
It can be written as a sum of positive squares in 4 ways, for example, as 118427521689 + 412076692624 = 344133^2 + 641932^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530504214313 - 21 = 530504214311 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530504214311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12058845 + ... + 12102757.
It is an arithmetic number, because the mean of its divisors is an integer number (66555465561).
Almost surely, 2530504214313 is an apocalyptic number.
It is an amenable number.
530504214313 is a deficient number, since it is larger than the sum of its proper divisors (1939510175).
530504214313 is a wasteful number, since it uses less digits than its factorization.
530504214313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87803.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 530504214313 its reverse (313412405035), we get a palindrome (843916619348).
The spelling of 530504214313 in words is "five hundred thirty billion, five hundred four million, two hundred fourteen thousand, three hundred thirteen".
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