Base | Representation |
---|---|
bin | 110001011010001110… |
… | …011001010000001001 |
3 | 12001221101012102120111 |
4 | 301122032121100021 |
5 | 1332123123033231 |
6 | 40212232554321 |
7 | 3555465603526 |
oct | 613216312011 |
9 | 161841172514 |
10 | 53053330441 |
11 | 20555249441 |
12 | a3475529a1 |
13 | 5006507527 |
14 | 27d405a14d |
15 | 15a79704b1 |
hex | c5a399409 |
53053330441 has 4 divisors (see below), whose sum is σ = 53131696452. Its totient is φ = 52974964432.
The previous prime is 53053330433. The next prime is 53053330453. The reversal of 53053330441 is 14403335035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 48232944400 + 4820386041 = 219620^2 + 69429^2 .
It is a cyclic number.
It is not a de Polignac number, because 53053330441 - 23 = 53053330433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53053330411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39181990 + ... + 39183343.
It is an arithmetic number, because the mean of its divisors is an integer number (13282924113).
Almost surely, 253053330441 is an apocalyptic number.
It is an amenable number.
53053330441 is a deficient number, since it is larger than the sum of its proper divisors (78366011).
53053330441 is an equidigital number, since it uses as much as digits as its factorization.
53053330441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78366010.
The product of its (nonzero) digits is 32400, while the sum is 31.
Adding to 53053330441 its reverse (14403335035), we get a palindrome (67456665476).
The spelling of 53053330441 in words is "fifty-three billion, fifty-three million, three hundred thirty thousand, four hundred forty-one".
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