Base | Representation |
---|---|
bin | 100110100110100010001… |
… | …0101111011101111111001 |
3 | 200210012020121211021000022 |
4 | 1031031010111323233321 |
5 | 1143411010342223001 |
6 | 15141140443220225 |
7 | 1055206350135065 |
oct | 115150425735771 |
9 | 20705217737008 |
10 | 5305431211001 |
11 | 1766025673a99 |
12 | 71828a217675 |
13 | 2c63b91a029c |
14 | 144ad9d56aa5 |
15 | 93016b1311b |
hex | 4d34457bbf9 |
5305431211001 has 4 divisors (see below), whose sum is σ = 5309645216400. Its totient is φ = 5301217205604.
The previous prime is 5305431210997. The next prime is 5305431211007. The reversal of 5305431211001 is 1001121345035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5305431211001 - 22 = 5305431210997 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5305431211007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2107000811 + ... + 2107003328.
It is an arithmetic number, because the mean of its divisors is an integer number (1327411304100).
Almost surely, 25305431211001 is an apocalyptic number.
It is an amenable number.
5305431211001 is a deficient number, since it is larger than the sum of its proper divisors (4214005399).
5305431211001 is a wasteful number, since it uses less digits than its factorization.
5305431211001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4214005398.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 5305431211001 its reverse (1001121345035), we get a palindrome (6306552556036).
The spelling of 5305431211001 in words is "five trillion, three hundred five billion, four hundred thirty-one million, two hundred eleven thousand, one".
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