Base | Representation |
---|---|
bin | 111100010100010010000100… |
… | …0000011100011000000010001 |
3 | 2120120112101102021001211101121 |
4 | 1320220210020003203000101 |
5 | 1024020040322431130441 |
6 | 5120220430310402241 |
7 | 216516125441213500 |
oct | 17050441003430021 |
9 | 2516471367054347 |
10 | 530553150255121 |
11 | 1440613669106a4 |
12 | 4b608908660381 |
13 | 19a06c41562cb6 |
14 | 9502ca38b6837 |
15 | 4150d89523dd1 |
hex | 1e289080e3011 |
530553150255121 has 12 divisors (see below), whose sum is σ = 617174641887732. Its totient is φ = 454759423708128.
The previous prime is 530553150255083. The next prime is 530553150255143. The reversal of 530553150255121 is 121552051355035.
It can be written as a sum of positive squares in 2 ways, for example, as 101740790648896 + 428812359606225 = 10086664^2 + 20707785^2 .
It is not a de Polignac number, because 530553150255121 - 213 = 530553150246929 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530553154255121) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 56281251 + ... + 65028343.
It is an arithmetic number, because the mean of its divisors is an integer number (51431220157311).
Almost surely, 2530553150255121 is an apocalyptic number.
It is an amenable number.
530553150255121 is a deficient number, since it is larger than the sum of its proper divisors (86621491632611).
530553150255121 is a wasteful number, since it uses less digits than its factorization.
530553150255121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9984960 (or 9984953 counting only the distinct ones).
The product of its (nonzero) digits is 562500, while the sum is 43.
The spelling of 530553150255121 in words is "five hundred thirty trillion, five hundred fifty-three billion, one hundred fifty million, two hundred fifty-five thousand, one hundred twenty-one".
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