Base | Representation |
---|---|
bin | 1111011100001111101… |
… | …11101100001011000001 |
3 | 1212201110200011222122100 |
4 | 13232013313230023001 |
5 | 32143041442003132 |
6 | 1043423000501013 |
7 | 53221532562243 |
oct | 7560767541301 |
9 | 1781420158570 |
10 | 530560500417 |
11 | 195011630812 |
12 | 869ab77a769 |
13 | 3b05468b90c |
14 | 1b971c92093 |
15 | dc03a7637c |
hex | 7b87dec2c1 |
530560500417 has 12 divisors (see below), whose sum is σ = 811445471460. Its totient is φ = 332900706048.
The previous prime is 530560500409. The next prime is 530560500433. The reversal of 530560500417 is 714005065035.
530560500417 is a `hidden beast` number, since 5 + 3 + 0 + 5 + 605 + 0 + 0 + 41 + 7 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 334310614416 + 196249886001 = 578196^2 + 443001^2 .
It is not a de Polignac number, because 530560500417 - 23 = 530560500409 is a prime.
It is not an unprimeable number, because it can be changed into a prime (530560500487) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1733857692 + ... + 1733857997.
It is an arithmetic number, because the mean of its divisors is an integer number (67620455955).
Almost surely, 2530560500417 is an apocalyptic number.
It is an amenable number.
530560500417 is a deficient number, since it is larger than the sum of its proper divisors (280884971043).
530560500417 is a wasteful number, since it uses less digits than its factorization.
530560500417 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3467715712 (or 3467715709 counting only the distinct ones).
The product of its (nonzero) digits is 63000, while the sum is 36.
The spelling of 530560500417 in words is "five hundred thirty billion, five hundred sixty million, five hundred thousand, four hundred seventeen".
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