Base | Representation |
---|---|
bin | 110001011010110000… |
… | …110010001010000001 |
3 | 12001222000011102200211 |
4 | 301122300302022001 |
5 | 1332132430022340 |
6 | 40213154114121 |
7 | 3555635331202 |
oct | 613260621201 |
9 | 161860142624 |
10 | 53062345345 |
11 | 2055a346479 |
12 | a34a57b941 |
13 | 50083428a9 |
14 | 27d53255a9 |
15 | 15a86515ea |
hex | c5ac32281 |
53062345345 has 16 divisors (see below), whose sum is σ = 65236021200. Its totient is φ = 41409331200.
The previous prime is 53062345319. The next prime is 53062345393. The reversal of 53062345345 is 54354326035.
It can be written as a sum of positive squares in 8 ways, for example, as 11105787456 + 41956557889 = 105384^2 + 204833^2 .
It is not a de Polignac number, because 53062345345 - 25 = 53062345313 is a prime.
It is a super-2 number, since 2×530623453452 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53062345298 and 53062345307.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2930881 + ... + 2948929.
It is an arithmetic number, because the mean of its divisors is an integer number (4077251325).
Almost surely, 253062345345 is an apocalyptic number.
It is an amenable number.
53062345345 is a deficient number, since it is larger than the sum of its proper divisors (12173675855).
53062345345 is a wasteful number, since it uses less digits than its factorization.
53062345345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32436.
The product of its (nonzero) digits is 648000, while the sum is 40.
The spelling of 53062345345 in words is "fifty-three billion, sixty-two million, three hundred forty-five thousand, three hundred forty-five".
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