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53063330051 = 188401281651
BaseRepresentation
bin110001011010110100…
…100010100100000011
312001222002000110110102
4301122310202210003
51332133203030201
640213231153015
73555646602104
oct613264424403
9161862013412
1053063330051
112055a959286
12a34a97576b
1350085c8b64
1427d55003ab
1515a879826b
hexc5ad22903

53063330051 has 4 divisors (see below), whose sum is σ = 53063800104. Its totient is φ = 53062860000.

The previous prime is 53063330011. The next prime is 53063330053. The reversal of 53063330051 is 15003336035.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53063330051 is a prime.

It is a super-2 number, since 2×530633300512 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53063329996 and 53063330023.

It is not an unprimeable number, because it can be changed into a prime (53063330053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47576 + ... + 329226.

It is an arithmetic number, because the mean of its divisors is an integer number (13265950026).

Almost surely, 253063330051 is an apocalyptic number.

53063330051 is a deficient number, since it is larger than the sum of its proper divisors (470053).

53063330051 is a wasteful number, since it uses less digits than its factorization.

53063330051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 470052.

The product of its (nonzero) digits is 12150, while the sum is 29.

Adding to 53063330051 its reverse (15003336035), we get a palindrome (68066666086).

The spelling of 53063330051 in words is "fifty-three billion, sixty-three million, three hundred thirty thousand, fifty-one".

Divisors: 1 188401 281651 53063330051