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530663000473 = 4312341000011
BaseRepresentation
bin1111011100011011111…
…10101100100110011001
31212201201211001112021201
413232031332230212121
532143244212003343
61043441101434201
753224216036234
oct7561576544631
91781654045251
10530663000473
1119506447a601
1286a19b6b961
133b06c999338
141b98173441b
15dc0ca7194d
hex7b8dfac999

530663000473 has 4 divisors (see below), whose sum is σ = 543004000528. Its totient is φ = 518322000420.

The previous prime is 530663000459. The next prime is 530663000477. The reversal of 530663000473 is 374000366035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 530663000473 - 233 = 522073065881 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530663000477) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6170499963 + ... + 6170500048.

It is an arithmetic number, because the mean of its divisors is an integer number (135751000132).

Almost surely, 2530663000473 is an apocalyptic number.

It is an amenable number.

530663000473 is a deficient number, since it is larger than the sum of its proper divisors (12341000055).

530663000473 is a wasteful number, since it uses less digits than its factorization.

530663000473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12341000054.

The product of its (nonzero) digits is 136080, while the sum is 37.

The spelling of 530663000473 in words is "five hundred thirty billion, six hundred sixty-three million, four hundred seventy-three", and thus it is an aban number.

Divisors: 1 43 12341000011 530663000473