Base | Representation |
---|---|
bin | 111100010101001001100111… |
… | …1101100000011101011000011 |
3 | 2120120221210101102021200020201 |
4 | 1320222103033230003223003 |
5 | 1024024014201144021132 |
6 | 5120351321514550031 |
7 | 216530551232335162 |
oct | 17052231754035303 |
9 | 2516853342250221 |
10 | 530672463657667 |
11 | 1440a7a2314aa01 |
12 | 4b627a66438317 |
13 | 19a15277421486 |
14 | 95089819733d9 |
15 | 415401e0a32e7 |
hex | 1e2a4cfb03ac3 |
530672463657667 has 16 divisors (see below), whose sum is σ = 561856827051520. Its totient is φ = 499815185493600.
The previous prime is 530672463657659. The next prime is 530672463657671. The reversal of 530672463657667 is 766756364276035.
It is not a de Polignac number, because 530672463657667 - 23 = 530672463657659 is a prime.
It is a super-3 number, since 3×5306724636576673 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 530672463657667.
It is not an unprimeable number, because it can be changed into a prime (530672463657607) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11583009 + ... + 34576162.
It is an arithmetic number, because the mean of its divisors is an integer number (35116051690720).
Almost surely, 2530672463657667 is an apocalyptic number.
530672463657667 is a deficient number, since it is larger than the sum of its proper divisors (31184363393853).
530672463657667 is a wasteful number, since it uses less digits than its factorization.
530672463657667 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46162714.
The product of its (nonzero) digits is 4800902400, while the sum is 73.
The spelling of 530672463657667 in words is "five hundred thirty trillion, six hundred seventy-two billion, four hundred sixty-three million, six hundred fifty-seven thousand, six hundred sixty-seven".
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