Base | Representation |
---|---|
bin | 100110100111010101110… |
… | …0110001110011111110001 |
3 | 200210100201100111110021012 |
4 | 1031032223212032133301 |
5 | 1143423032331112340 |
6 | 15142024405040305 |
7 | 1055300313506300 |
oct | 115165346163761 |
9 | 20710640443235 |
10 | 5307163535345 |
11 | 1766834504a01 |
12 | 7186923b6095 |
13 | 2c6604056789 |
14 | 144c22054437 |
15 | 930b8c4e565 |
hex | 4d3ab98e7f1 |
5307163535345 has 12 divisors (see below), whose sum is σ = 7408367057844. Its totient is φ = 3639197852640.
The previous prime is 5307163535213. The next prime is 5307163535369. The reversal of 5307163535345 is 5435353617035.
It can be written as a sum of positive squares in 2 ways, for example, as 1172126691904 + 4135036843441 = 1082648^2 + 2033479^2 .
It is not a de Polignac number, because 5307163535345 - 222 = 5307159341041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5307163535293 and 5307163535302.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10830945746 + ... + 10830946235.
It is an arithmetic number, because the mean of its divisors is an integer number (617363921487).
Almost surely, 25307163535345 is an apocalyptic number.
It is an amenable number.
5307163535345 is a deficient number, since it is larger than the sum of its proper divisors (2101203522499).
5307163535345 is a wasteful number, since it uses less digits than its factorization.
5307163535345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21661892000 (or 21661891993 counting only the distinct ones).
The product of its (nonzero) digits is 8505000, while the sum is 50.
The spelling of 5307163535345 in words is "five trillion, three hundred seven billion, one hundred sixty-three million, five hundred thirty-five thousand, three hundred forty-five".
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