Base | Representation |
---|---|
bin | 110001011011010111… |
… | …100101010010001001 |
3 | 12001222201022011112101 |
4 | 301123113211102021 |
5 | 1332143031004413 |
6 | 40214200113401 |
7 | 3556120642012 |
oct | 613327452211 |
9 | 161881264471 |
10 | 53072516233 |
11 | 20565062a70 |
12 | a351a65861 |
13 | 500a494179 |
14 | 27d6812009 |
15 | 15a94aeedd |
hex | c5b5e5489 |
53072516233 has 4 divisors (see below), whose sum is σ = 57897290448. Its totient is φ = 48247742020.
The previous prime is 53072516197. The next prime is 53072516239. The reversal of 53072516233 is 33261527035.
53072516233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53072516233 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53072516192 and 53072516201.
It is not an unprimeable number, because it can be changed into a prime (53072516239) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2412387091 + ... + 2412387112.
It is an arithmetic number, because the mean of its divisors is an integer number (14474322612).
Almost surely, 253072516233 is an apocalyptic number.
It is an amenable number.
53072516233 is a deficient number, since it is larger than the sum of its proper divisors (4824774215).
53072516233 is a wasteful number, since it uses less digits than its factorization.
53072516233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4824774214.
The product of its (nonzero) digits is 113400, while the sum is 37.
The spelling of 53072516233 in words is "fifty-three billion, seventy-two million, five hundred sixteen thousand, two hundred thirty-three".
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