5308544443 has 4 divisors (see below), whose sum is σ = 5308847920. Its totient is φ = 5308240968.

The previous prime is 5308544441. The next prime is 5308544473. The reversal of 5308544443 is 3444458035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5308544443 - 2¹ = 5308544441 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5308544396 and 5308544405.

It is not an unprimeable number, because it can be changed into a prime (5308544441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123783 + ... + 161056.

It is an arithmetic number, because the mean of its divisors is an integer number (1327211980).

Almost surely, 2^5308544443 is an apocalyptic number.

5308544443 is a deficient number, since it is larger than the sum of its proper divisors (303477).

5308544443 is a wasteful number, since it uses less digits than its factorization.

5308544443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 303476.

The product of its (nonzero) digits is 460800, while the sum is 40.

The square root of 5308544443 is about 72859.7587355325. The cubic root of 5308544443 is about 1744.4498385234.

The spelling of 5308544443 in words is "five billion, three hundred eight million, five hundred forty-four thousand, four hundred forty-three".