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53089429433 = 233272275879
BaseRepresentation
bin110001011100011000…
…000110011110111001
312002000220010110002012
4301130120012132321
51332211343220213
640220002415305
73556414463435
oct613430063671
9162026113065
1053089429433
1120573665117
12a357661535
135010b36591
1427d8b759c5
1515aac014a8
hexc5c6067b9

53089429433 has 4 divisors (see below), whose sum is σ = 53091728640. Its totient is φ = 53087130228.

The previous prime is 53089429417. The next prime is 53089429439. The reversal of 53089429433 is 33492498035.

53089429433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33492498035 = 56698499607.

It is a cyclic number.

It is not a de Polignac number, because 53089429433 - 24 = 53089429417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53089429439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1114613 + ... + 1161266.

It is an arithmetic number, because the mean of its divisors is an integer number (13272932160).

Almost surely, 253089429433 is an apocalyptic number.

It is an amenable number.

53089429433 is a deficient number, since it is larger than the sum of its proper divisors (2299207).

53089429433 is a wasteful number, since it uses less digits than its factorization.

53089429433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2299206.

The product of its (nonzero) digits is 2799360, while the sum is 50.

The spelling of 53089429433 in words is "fifty-three billion, eighty-nine million, four hundred twenty-nine thousand, four hundred thirty-three".

Divisors: 1 23327 2275879 53089429433