Base | Representation |
---|---|
bin | 100110101000101010101… |
… | …0101100111111111010011 |
3 | 200210122001211002101201212 |
4 | 1031101111111213333103 |
5 | 1143444400343410120 |
6 | 15143215134450335 |
7 | 1055431013263355 |
oct | 115212525477723 |
9 | 20718054071655 |
10 | 5310011310035 |
11 | 1767a65a53203 |
12 | 7191480639ab |
13 | 2c6969040263 |
14 | 1450123530d5 |
15 | 931d3c746c5 |
hex | 4d455567fd3 |
5310011310035 has 16 divisors (see below), whose sum is σ = 6393981271104. Its totient is φ = 4233364916352.
The previous prime is 5310011309959. The next prime is 5310011310059. The reversal of 5310011310035 is 5300131100135.
5310011310035 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 5310011310035 - 242 = 911964798931 is a prime.
It is a super-2 number, since 2×53100113100352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 67267049 + ... + 67345941.
It is an arithmetic number, because the mean of its divisors is an integer number (399623829444).
Almost surely, 25310011310035 is an apocalyptic number.
5310011310035 is a deficient number, since it is larger than the sum of its proper divisors (1083969961069).
5310011310035 is a wasteful number, since it uses less digits than its factorization.
5310011310035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 125134.
The product of its (nonzero) digits is 675, while the sum is 23.
The spelling of 5310011310035 in words is "five trillion, three hundred ten billion, eleven million, three hundred ten thousand, thirty-five".
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