Search a number
-
+
5310011310035 = 52934594378893
BaseRepresentation
bin100110101000101010101…
…0101100111111111010011
3200210122001211002101201212
41031101111111213333103
51143444400343410120
615143215134450335
71055431013263355
oct115212525477723
920718054071655
105310011310035
111767a65a53203
127191480639ab
132c6969040263
141450123530d5
15931d3c746c5
hex4d455567fd3

5310011310035 has 16 divisors (see below), whose sum is σ = 6393981271104. Its totient is φ = 4233364916352.

The previous prime is 5310011309959. The next prime is 5310011310059. The reversal of 5310011310035 is 5300131100135.

5310011310035 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 5310011310035 - 242 = 911964798931 is a prime.

It is a super-2 number, since 2×53100113100352 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 67267049 + ... + 67345941.

It is an arithmetic number, because the mean of its divisors is an integer number (399623829444).

Almost surely, 25310011310035 is an apocalyptic number.

5310011310035 is a deficient number, since it is larger than the sum of its proper divisors (1083969961069).

5310011310035 is a wasteful number, since it uses less digits than its factorization.

5310011310035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 125134.

The product of its (nonzero) digits is 675, while the sum is 23.

The spelling of 5310011310035 in words is "five trillion, three hundred ten billion, eleven million, three hundred ten thousand, thirty-five".

Divisors: 1 5 293 1465 45943 78893 229715 394465 13461299 23115649 67306495 115578245 3624581099 18122905495 1062002262007 5310011310035