Base | Representation |
---|---|
bin | 100110101000101010101… |
… | …0101101101001001001001 |
3 | 200210122001211010110200201 |
4 | 1031101111111231021021 |
5 | 1143444400400044040 |
6 | 15143215135132201 |
7 | 1055431013412043 |
oct | 115212525551111 |
9 | 20718054113621 |
10 | 5310011331145 |
11 | 1767a65a68054 |
12 | 719148074061 |
13 | 2c6969049a51 |
14 | 14501235aa93 |
15 | 931d3c7aa9a |
hex | 4d45556d249 |
5310011331145 has 8 divisors (see below), whose sum is σ = 6591738204360. Its totient is φ = 4101525993600.
The previous prime is 5310011331113. The next prime is 5310011331167. The reversal of 5310011331145 is 5411331100135.
It can be written as a sum of positive squares in 4 ways, for example, as 1581547699216 + 3728463631929 = 1257596^2 + 1930923^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5310011331145 - 25 = 5310011331113 is a prime.
It is a super-2 number, since 2×53100113311452 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18310383756 + ... + 18310384045.
It is an arithmetic number, because the mean of its divisors is an integer number (823967275545).
Almost surely, 25310011331145 is an apocalyptic number.
It is an amenable number.
5310011331145 is a deficient number, since it is larger than the sum of its proper divisors (1281726873215).
5310011331145 is a wasteful number, since it uses less digits than its factorization.
5310011331145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36620767835.
The product of its (nonzero) digits is 2700, while the sum is 28.
The spelling of 5310011331145 in words is "five trillion, three hundred ten billion, eleven million, three hundred thirty-one thousand, one hundred forty-five".
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