Base | Representation |
---|---|
bin | 110001011101000101… |
… | …011000100110110001 |
3 | 12002001201110112122012 |
4 | 301131011120212301 |
5 | 1332222413101040 |
6 | 40221105052305 |
7 | 3556620414065 |
oct | 613505304661 |
9 | 162051415565 |
10 | 53101300145 |
11 | 2057a332823 |
12 | a35b627095 |
13 | 501343177a |
14 | 27da585aa5 |
15 | 15abc98865 |
hex | c5d1589b1 |
53101300145 has 16 divisors (see below), whose sum is σ = 64018093392. Its totient is φ = 42283530240.
The previous prime is 53101300141. The next prime is 53101300171. The reversal of 53101300145 is 54100310135.
It can be written as a sum of positive squares in 8 ways, for example, as 466387216 + 52634912929 = 21596^2 + 229423^2 .
It is not a de Polignac number, because 53101300145 - 22 = 53101300141 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 53101300145.
It is not an unprimeable number, because it can be changed into a prime (53101300141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2656709 + ... + 2676621.
It is an arithmetic number, because the mean of its divisors is an integer number (4001130837).
Almost surely, 253101300145 is an apocalyptic number.
It is an amenable number.
53101300145 is a deficient number, since it is larger than the sum of its proper divisors (10916793247).
53101300145 is a wasteful number, since it uses less digits than its factorization.
53101300145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22372.
The product of its (nonzero) digits is 900, while the sum is 23.
The spelling of 53101300145 in words is "fifty-three billion, one hundred one million, three hundred thousand, one hundred forty-five".
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