Base | Representation |
---|---|
bin | 110001011101001101… |
… | …000110110010010001 |
3 | 12002001212021101021002 |
4 | 301131031012302101 |
5 | 1332223422334210 |
6 | 40221220311345 |
7 | 3556643544323 |
oct | 613515066221 |
9 | 162055241232 |
10 | 53103324305 |
11 | 20580495589 |
12 | a360242555 |
13 | 501398cbb5 |
14 | 27da951613 |
15 | 15ac0484a5 |
hex | c5d346c91 |
53103324305 has 8 divisors (see below), whose sum is σ = 63752087400. Its totient is φ = 42463927296.
The previous prime is 53103324293. The next prime is 53103324317. The reversal of 53103324305 is 50342330135.
It is an interprime number because it is at equal distance from previous prime (53103324293) and next prime (53103324317).
It can be written as a sum of positive squares in 4 ways, for example, as 611473984 + 52491850321 = 24728^2 + 229111^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53103324305 - 28 = 53103324049 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2329040 + ... + 2351729.
It is an arithmetic number, because the mean of its divisors is an integer number (7969010925).
Almost surely, 253103324305 is an apocalyptic number.
It is an amenable number.
53103324305 is a deficient number, since it is larger than the sum of its proper divisors (10648763095).
53103324305 is a wasteful number, since it uses less digits than its factorization.
53103324305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4683043.
The product of its (nonzero) digits is 16200, while the sum is 29.
The spelling of 53103324305 in words is "fifty-three billion, one hundred three million, three hundred twenty-four thousand, three hundred five".
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