Base | Representation |
---|---|
bin | 111100010111110100110010… |
… | …0010111010011110011001011 |
3 | 2120122020221010202122220220220 |
4 | 1320233221210113103303023 |
5 | 1024101024440220302133 |
6 | 5121232231054321123 |
7 | 216566242665640035 |
oct | 17057514427236313 |
9 | 2518227122586826 |
10 | 531040030244043 |
11 | 1442298a2984631 |
12 | 4b6871477b91a3 |
13 | 19a40b244b00b8 |
14 | 951c690450c55 |
15 | 415d8833eb5b3 |
hex | 1e2fa645d3ccb |
531040030244043 has 12 divisors (see below), whose sum is σ = 727707156132600. Its totient is φ = 344458397993472.
The previous prime is 531040030244039. The next prime is 531040030244081. The reversal of 531040030244043 is 340442030040135.
It is not a de Polignac number, because 531040030244043 - 22 = 531040030244039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 531040030243995 and 531040030244013.
It is not an unprimeable number, because it can be changed into a prime (531040030244083) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 64650596118 + ... + 64650604331.
It is an arithmetic number, because the mean of its divisors is an integer number (60642263011050).
Almost surely, 2531040030244043 is an apocalyptic number.
531040030244043 is a deficient number, since it is larger than the sum of its proper divisors (196667125888557).
531040030244043 is a wasteful number, since it uses less digits than its factorization.
531040030244043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 129301200526 (or 129301200489 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 33.
Adding to 531040030244043 its reverse (340442030040135), we get a palindrome (871482060284178).
The spelling of 531040030244043 in words is "five hundred thirty-one trillion, forty billion, thirty million, two hundred forty-four thousand, forty-three".
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