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531042631451 = 1573382437143
BaseRepresentation
bin1111011101001001001…
…10110111111100011011
31212202201021101210002022
413232210212313330123
532200033403201301
61043542502325055
753236505614133
oct7564446677433
91782637353068
10531042631451
111952397a2a12
1286b0512978b
133b100528557
141b9b9d15ac3
15dc3105ed1b
hex7ba49b7f1b

531042631451 has 4 divisors (see below), whose sum is σ = 534425068752. Its totient is φ = 527660194152.

The previous prime is 531042631411. The next prime is 531042631481. The reversal of 531042631451 is 154136240135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 531042631451 - 218 = 531042369307 is a prime.

It is a super-2 number, since 2×5310426314512 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (531042631411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1691218415 + ... + 1691218728.

It is an arithmetic number, because the mean of its divisors is an integer number (133606267188).

Almost surely, 2531042631451 is an apocalyptic number.

531042631451 is a deficient number, since it is larger than the sum of its proper divisors (3382437301).

531042631451 is a wasteful number, since it uses less digits than its factorization.

531042631451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3382437300.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 531042631451 its reverse (154136240135), we get a palindrome (685178871586).

The spelling of 531042631451 in words is "five hundred thirty-one billion, forty-two million, six hundred thirty-one thousand, four hundred fifty-one".

Divisors: 1 157 3382437143 531042631451