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53105113 = 211389647
BaseRepresentation
bin1100101010010…
…1000111011001
310200221000112001
43022211013121
5102043330423
65134121001
71213246255
oct312450731
9120830461
1053105113
1127a81726
1215950161
13b004859
1470a5265
1549decad
hex32a51d9

53105113 has 8 divisors (see below), whose sum is σ = 53576640. Its totient is φ = 52636080.

The previous prime is 53105111. The next prime is 53105123. The reversal of 53105113 is 31150135.

53105113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53105113 - 21 = 53105111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53105111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81756 + ... + 82402.

It is an arithmetic number, because the mean of its divisors is an integer number (6697080).

Almost surely, 253105113 is an apocalyptic number.

It is an amenable number.

53105113 is a deficient number, since it is larger than the sum of its proper divisors (471527).

53105113 is a wasteful number, since it uses less digits than its factorization.

53105113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1247.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 53105113 is about 7287.3255039143. The cubic root of 53105113 is about 375.8767350016.

Adding to 53105113 its reverse (31150135), we get a palindrome (84255248).

The spelling of 53105113 in words is "fifty-three million, one hundred five thousand, one hundred thirteen".

Divisors: 1 211 389 647 82079 136517 251683 53105113