Base | Representation |
---|---|
bin | 110001011101011000… |
… | …111110100011011001 |
3 | 12002002002010111010122 |
4 | 301131120332203121 |
5 | 1332230221430223 |
6 | 40221411123025 |
7 | 3560012155250 |
oct | 613530764331 |
9 | 162062114118 |
10 | 53106436313 |
11 | 20582220697 |
12 | a3612a3475 |
13 | 501450c518 |
14 | 27db121797 |
15 | 15ac4605c8 |
hex | c5d63e8d9 |
53106436313 has 4 divisors (see below), whose sum is σ = 60693070080. Its totient is φ = 45519802548.
The previous prime is 53106436301. The next prime is 53106436321. The reversal of 53106436313 is 31363460135.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53106436313 - 24 = 53106436297 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (53106436333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3793316873 + ... + 3793316886.
It is an arithmetic number, because the mean of its divisors is an integer number (15173267520).
Almost surely, 253106436313 is an apocalyptic number.
It is an amenable number.
53106436313 is a deficient number, since it is larger than the sum of its proper divisors (7586633767).
53106436313 is an equidigital number, since it uses as much as digits as its factorization.
53106436313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7586633766.
The product of its (nonzero) digits is 58320, while the sum is 35.
Adding to 53106436313 its reverse (31363460135), we get a palindrome (84469896448).
The spelling of 53106436313 in words is "fifty-three billion, one hundred six million, four hundred thirty-six thousand, three hundred thirteen".
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