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5311111041 = 32590123449
BaseRepresentation
bin1001111001001000…
…10001111110000001
3111201010210101200100
410330210101332001
541334121023131
62235003313013
7245420461515
oct47444217601
914633711610
105311111041
112285a90375
12104281b769
13668449b72
14385528145
1521140c7e6
hex13c911f81

5311111041 has 6 divisors (see below), whose sum is σ = 7671604850. Its totient is φ = 3540740688.

The previous prime is 5311111027. The next prime is 5311111063. The reversal of 5311111041 is 1401111135.

It can be written as a sum of positive squares in only one way, i.e., 5220785025 + 90326016 = 72255^2 + 9504^2 .

It is not a de Polignac number, because 5311111041 - 25 = 5311111009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5311111241) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 295061716 + ... + 295061733.

Almost surely, 25311111041 is an apocalyptic number.

It is an amenable number.

5311111041 is a deficient number, since it is larger than the sum of its proper divisors (2360493809).

5311111041 is a wasteful number, since it uses less digits than its factorization.

5311111041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 590123455 (or 590123452 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 18.

The square root of 5311111041 is about 72877.3698825637. The cubic root of 5311111041 is about 1744.7309312749.

Adding to 5311111041 its reverse (1401111135), we get a palindrome (6712222176).

The spelling of 5311111041 in words is "five billion, three hundred eleven million, one hundred eleven thousand, forty-one".

Divisors: 1 3 9 590123449 1770370347 5311111041