53111404011 has 4 divisors (see below), whose sum is σ = 70815205352. Its totient is φ = 35407602672.

The previous prime is 53111403991. The next prime is 53111404037. The reversal of 53111404011 is 11040411135.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 53111404011 - 2³¹ = 50963920363 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53111404091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8851900666 + ... + 8851900671.

It is an arithmetic number, because the mean of its divisors is an integer number (17703801338).

Almost surely, 2^53111404011 is an apocalyptic number.

53111404011 is a deficient number, since it is larger than the sum of its proper divisors (17703801341).

53111404011 is a wasteful number, since it uses less digits than its factorization.

53111404011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17703801340.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 53111404011 its reverse (11040411135), we get a palindrome (64151815146).

The spelling of 53111404011 in words is "fifty-three billion, one hundred eleven million, four hundred four thousand, eleven".