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53112433 = 114828403
BaseRepresentation
bin1100101010011…
…0111001110001
310200221101120011
43022212321301
5102044044213
65134214521
71213306513
oct312467161
9120841504
1053112433
1127a87180
1215954441
13b007c9a
1470a7bb3
1549e203d
hex32a6e71

53112433 has 4 divisors (see below), whose sum is σ = 57940848. Its totient is φ = 48284020.

The previous prime is 53112431. The next prime is 53112457. The reversal of 53112433 is 33421135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53112433 - 21 = 53112431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53112431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2414191 + ... + 2414212.

It is an arithmetic number, because the mean of its divisors is an integer number (14485212).

Almost surely, 253112433 is an apocalyptic number.

It is an amenable number.

53112433 is a deficient number, since it is larger than the sum of its proper divisors (4828415).

53112433 is a wasteful number, since it uses less digits than its factorization.

53112433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4828414.

The product of its digits is 1080, while the sum is 22.

The square root of 53112433 is about 7287.8277284799. The cubic root of 53112433 is about 375.8940044705.

Adding to 53112433 its reverse (33421135), we get a palindrome (86533568).

It can be divided in two parts, 5311 and 2433, that added together give a square (7744 = 882).

The spelling of 53112433 in words is "fifty-three million, one hundred twelve thousand, four hundred thirty-three".

Divisors: 1 11 4828403 53112433