Base | Representation |
---|---|
bin | 11000001001110100110001… |
… | …11100010110110010000011 |
3 | 20222001122212011001112220122 |
4 | 30010322120330112302003 |
5 | 23430210220133303443 |
6 | 304544143431530455 |
7 | 14121240456652112 |
oct | 1404723074266203 |
9 | 228048764045818 |
10 | 53114131541123 |
11 | 15a18638632974 |
12 | 5b59a5b229a2b |
13 | 23838446a9563 |
14 | d18a482b9c79 |
15 | 621949056968 |
hex | 304e98f16c83 |
53114131541123 has 8 divisors (see below), whose sum is σ = 54549952018560. Its totient is φ = 51678327032640.
The previous prime is 53114131541087. The next prime is 53114131541153. The reversal of 53114131541123 is 32114513141135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53114131541123 - 226 = 53114064432259 is a prime.
It is a super-2 number, since 2×531141315411232 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53114131541153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2908943 + ... + 10709351.
It is an arithmetic number, because the mean of its divisors is an integer number (6818744002320).
Almost surely, 253114131541123 is an apocalyptic number.
53114131541123 is a deficient number, since it is larger than the sum of its proper divisors (1435820477437).
53114131541123 is a wasteful number, since it uses less digits than its factorization.
53114131541123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7984477.
The product of its digits is 21600, while the sum is 35.
Adding to 53114131541123 its reverse (32114513141135), we get a palindrome (85228644682258).
The spelling of 53114131541123 in words is "fifty-three trillion, one hundred fourteen billion, one hundred thirty-one million, five hundred forty-one thousand, one hundred twenty-three".
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