Base | Representation |
---|---|
bin | 110001011101110110… |
… | …010111100101101001 |
3 | 12002002121121221000122 |
4 | 301131312113211221 |
5 | 1332234210003113 |
6 | 40222244213025 |
7 | 3560134515062 |
oct | 613566274551 |
9 | 162077557018 |
10 | 53114141033 |
11 | 20586603328 |
12 | a36399a175 |
13 | 5015ca9425 |
14 | 27dc169569 |
15 | 15ace83408 |
hex | c5dd97969 |
53114141033 has 8 divisors (see below), whose sum is σ = 56218518720. Its totient is φ = 50040653040.
The previous prime is 53114141011. The next prime is 53114141039. The reversal of 53114141033 is 33014141135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53114141033 - 224 = 53097363817 is a prime.
It is a super-2 number, since 2×531141410332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53114140993 and 53114141011.
It is not an unprimeable number, because it can be changed into a prime (53114141039) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7718885 + ... + 7725762.
It is an arithmetic number, because the mean of its divisors is an integer number (7027314840).
Almost surely, 253114141033 is an apocalyptic number.
It is an amenable number.
53114141033 is a deficient number, since it is larger than the sum of its proper divisors (3104377687).
53114141033 is a wasteful number, since it uses less digits than its factorization.
53114141033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15444847.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 53114141033 its reverse (33014141135), we get a palindrome (86128282168).
The spelling of 53114141033 in words is "fifty-three billion, one hundred fourteen million, one hundred forty-one thousand, thirty-three".
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