Base | Representation |
---|---|
bin | 1001111001001010… |
… | …11110100011110001 |
3 | 111201011101100000022 |
4 | 10330211132203301 |
5 | 41334211043003 |
6 | 2235014133225 |
7 | 245423236235 |
oct | 47445364361 |
9 | 14634340008 |
10 | 5311424753 |
11 | 2286185038 |
12 | 1042951215 |
13 | 6685298ab |
14 | 3855aa5c5 |
15 | 211470738 |
hex | 13c95e8f1 |
5311424753 has 4 divisors (see below), whose sum is σ = 5542356288. Its totient is φ = 5080493220.
The previous prime is 5311424747. The next prime is 5311424821. The reversal of 5311424753 is 3574241135.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5311424753 - 28 = 5311424497 is a prime.
It is a super-2 number, since 2×53114247532 = 56422465813562222018, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5317424753) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115465733 + ... + 115465778.
It is an arithmetic number, because the mean of its divisors is an integer number (1385589072).
Almost surely, 25311424753 is an apocalyptic number.
It is an amenable number.
5311424753 is a deficient number, since it is larger than the sum of its proper divisors (230931535).
5311424753 is a wasteful number, since it uses less digits than its factorization.
5311424753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 230931534.
The product of its digits is 50400, while the sum is 35.
The square root of 5311424753 is about 72879.5221787300. The cubic root of 5311424753 is about 1744.7652826720.
Adding to 5311424753 its reverse (3574241135), we get a palindrome (8885665888).
The spelling of 5311424753 in words is "five billion, three hundred eleven million, four hundred twenty-four thousand, seven hundred fifty-three".
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