Base | Representation |
---|---|
bin | 100110101001011000101… |
… | …0111100010000110000001 |
3 | 200210210001102101221001201 |
4 | 1031102301113202012001 |
5 | 1144011031130022144 |
6 | 15144032252101201 |
7 | 1055514202143655 |
oct | 115226127420601 |
9 | 20723042357051 |
10 | 5311555314049 |
11 | 1768688559286 |
12 | 7194b9164801 |
13 | 2c6b53b9b6ba |
14 | 14511b42ca65 |
15 | 932745b21d4 |
hex | 4d4b15e2181 |
5311555314049 has 4 divisors (see below), whose sum is σ = 5328311009364. Its totient is φ = 5294799618736.
The previous prime is 5311555314007. The next prime is 5311555314053. The reversal of 5311555314049 is 9404135551135.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1827146958400 + 3484408355649 = 1351720^2 + 1866657^2 .
It is a cyclic number.
It is not a de Polignac number, because 5311555314049 - 215 = 5311555281281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5311555314059) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8377847182 + ... + 8377847815.
It is an arithmetic number, because the mean of its divisors is an integer number (1332077752341).
Almost surely, 25311555314049 is an apocalyptic number.
It is an amenable number.
5311555314049 is a deficient number, since it is larger than the sum of its proper divisors (16755695315).
5311555314049 is a wasteful number, since it uses less digits than its factorization.
5311555314049 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16755695314.
The product of its (nonzero) digits is 810000, while the sum is 46.
The spelling of 5311555314049 in words is "five trillion, three hundred eleven billion, five hundred fifty-five million, three hundred fourteen thousand, forty-nine".
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