Base | Representation |
---|---|
bin | 100110101001011010000… |
… | …0010100000100011001001 |
3 | 200210210011112202000221200 |
4 | 1031102310002200203021 |
5 | 1144011124113244340 |
6 | 15144040532454413 |
7 | 1055515255126251 |
oct | 115226402404311 |
9 | 20723145660850 |
10 | 5311600134345 |
11 | 176870089144a |
12 | 71951017a409 |
13 | 2c6b6026229b |
14 | 145123378961 |
15 | 932784b7330 |
hex | 4d4b40a08c9 |
5311600134345 has 12 divisors (see below), whose sum is σ = 9206773566276. Its totient is φ = 2832853404960.
The previous prime is 5311600134331. The next prime is 5311600134377. The reversal of 5311600134345 is 5434310061135.
5311600134345 is a `hidden beast` number, since 5 + 3 + 1 + 1 + 600 + 1 + 3 + 4 + 3 + 45 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 1378632919104 + 3932967215241 = 1174152^2 + 1983171^2 .
It is not a de Polignac number, because 5311600134345 - 237 = 5174161180873 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 59017779226 + ... + 59017779315.
It is an arithmetic number, because the mean of its divisors is an integer number (767231130523).
Almost surely, 25311600134345 is an apocalyptic number.
It is an amenable number.
5311600134345 is a deficient number, since it is larger than the sum of its proper divisors (3895173431931).
5311600134345 is a wasteful number, since it uses less digits than its factorization.
5311600134345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118035558552 (or 118035558549 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 36.
The spelling of 5311600134345 in words is "five trillion, three hundred eleven billion, six hundred million, one hundred thirty-four thousand, three hundred forty-five".
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