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53117113 = 77588159
BaseRepresentation
bin1100101010100…
…0000010111001
310200221121222111
43022220002321
5102044221423
65134252321
71213326250
oct312500271
9120847874
1053117113
1127a8a745
12159570a1
13b00a15a
1470a9797
1549e360d
hex32a80b9

53117113 has 4 divisors (see below), whose sum is σ = 60705280. Its totient is φ = 45528948.

The previous prime is 53117111. The next prime is 53117161. The reversal of 53117113 is 31171135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53117113 - 21 = 53117111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53117111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3794073 + ... + 3794086.

It is an arithmetic number, because the mean of its divisors is an integer number (15176320).

Almost surely, 253117113 is an apocalyptic number.

It is an amenable number.

53117113 is a deficient number, since it is larger than the sum of its proper divisors (7588167).

53117113 is an equidigital number, since it uses as much as digits as its factorization.

53117113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7588166.

The product of its digits is 315, while the sum is 22.

The square root of 53117113 is about 7288.1488047377. The cubic root of 53117113 is about 375.9050447748.

Adding to 53117113 its reverse (31171135), we get a palindrome (84288248).

The spelling of 53117113 in words is "fifty-three million, one hundred seventeen thousand, one hundred thirteen".

Divisors: 1 7 7588159 53117113