5312313035 has 4 divisors (see below), whose sum is σ = 6374775648. Its totient is φ = 4249850424.

The previous prime is 5312313011. The next prime is 5312313043. The reversal of 5312313035 is 5303132135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5312313035 - 2²⁰ = 5311264459 is a prime.

It is a super-2 number, since 2×5312313035² = 56441339563661822450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5312312995 and 5312313013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 531231299 + ... + 531231308.

It is an arithmetic number, because the mean of its divisors is an integer number (1593693912).

Almost surely, 2^5312313035 is an apocalyptic number.

5312313035 is a deficient number, since it is larger than the sum of its proper divisors (1062462613).

5312313035 is a wasteful number, since it uses less digits than its factorization.

5312313035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1062462612.

The product of its (nonzero) digits is 4050, while the sum is 26.

The square root of 5312313035 is about 72885.6161049627. The cubic root of 5312313035 is about 1744.8625420250.

Subtracting from 5312313035 its reverse (5303132135), we obtain a square (9180900 = 3030²).

The spelling of 5312313035 in words is "five billion, three hundred twelve million, three hundred thirteen thousand, thirty-five".