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5312436175313 = 5990041291107
BaseRepresentation
bin100110101001110010111…
…0111110000000111010001
3200210212022210220022112222
41031103211313300013101
51144014332130102223
615144255520030425
71055545056301421
oct115234567600721
920725283808488
105312436175313
111768a9a7a93a3
12719704162415
132c6c64523997
141451a2406481
15932c6aad0c8
hex4d4e5df01d1

5312436175313 has 4 divisors (see below), whose sum is σ = 5402477466480. Its totient is φ = 5222394884148.

The previous prime is 5312436175289. The next prime is 5312436175331. The reversal of 5312436175313 is 3135716342135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5312436175313 - 210 = 5312436174289 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (5312436175363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45020645495 + ... + 45020645612.

It is an arithmetic number, because the mean of its divisors is an integer number (1350619366620).

Almost surely, 25312436175313 is an apocalyptic number.

It is an amenable number.

5312436175313 is a deficient number, since it is larger than the sum of its proper divisors (90041291167).

5312436175313 is an equidigital number, since it uses as much as digits as its factorization.

5312436175313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 90041291166.

The product of its digits is 680400, while the sum is 44.

The spelling of 5312436175313 in words is "five trillion, three hundred twelve billion, four hundred thirty-six million, one hundred seventy-five thousand, three hundred thirteen".

Divisors: 1 59 90041291107 5312436175313