Base | Representation |
---|---|
bin | 100110101001110011000… |
… | …1110000110110011111011 |
3 | 200210212100012221001011010 |
4 | 1031103212032012303323 |
5 | 1144014340130113301 |
6 | 15144300245405003 |
7 | 1055545160146365 |
oct | 115234616066373 |
9 | 20725305831133 |
10 | 5312442035451 |
11 | 1768aa3041191 |
12 | 719706109763 |
13 | 2c6c657c6115 |
14 | 1451a30cdd35 |
15 | 932c73695d6 |
hex | 4d4e6386cfb |
5312442035451 has 4 divisors (see below), whose sum is σ = 7083256047272. Its totient is φ = 3541628023632.
The previous prime is 5312442035449. The next prime is 5312442035471. The reversal of 5312442035451 is 1545302442135.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5312442035451 - 21 = 5312442035449 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5312442035471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 885407005906 + ... + 885407005911.
It is an arithmetic number, because the mean of its divisors is an integer number (1770814011818).
Almost surely, 25312442035451 is an apocalyptic number.
5312442035451 is a deficient number, since it is larger than the sum of its proper divisors (1770814011821).
5312442035451 is a wasteful number, since it uses less digits than its factorization.
5312442035451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1770814011820.
The product of its (nonzero) digits is 288000, while the sum is 39.
Adding to 5312442035451 its reverse (1545302442135), we get a palindrome (6857744477586).
The spelling of 5312442035451 in words is "five trillion, three hundred twelve billion, four hundred forty-two million, thirty-five thousand, four hundred fifty-one".
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