Base | Representation |
---|---|
bin | 1111011101101000011… |
… | …01010010110110111001 |
3 | 1212210101111220001002011 |
4 | 13232310031102312321 |
5 | 32201102404031101 |
6 | 1044024452205521 |
7 | 53246134362202 |
oct | 7566415226671 |
9 | 1783344801064 |
10 | 531304361401 |
11 | 195363508560 |
12 | 86b789098a1 |
13 | 3b142817048 |
14 | 1ba029a65a9 |
15 | dc4900e751 |
hex | 7bb4352db9 |
531304361401 has 16 divisors (see below), whose sum is σ = 601874941248. Its totient is φ = 464768236800.
The previous prime is 531304361387. The next prime is 531304361449. The reversal of 531304361401 is 104163403135.
It is a cyclic number.
It is not a de Polignac number, because 531304361401 - 217 = 531304230329 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (531304361101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8035971 + ... + 8101816.
It is an arithmetic number, because the mean of its divisors is an integer number (37617183828).
Almost surely, 2531304361401 is an apocalyptic number.
It is an amenable number.
531304361401 is a deficient number, since it is larger than the sum of its proper divisors (70570579847).
531304361401 is a wasteful number, since it uses less digits than its factorization.
531304361401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16137912.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 531304361401 its reverse (104163403135), we get a palindrome (635467764536).
The spelling of 531304361401 in words is "five hundred thirty-one billion, three hundred four million, three hundred sixty-one thousand, four hundred one".
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