Base | Representation |
---|---|
bin | 110001011110110100… |
… | …110110011100011001 |
3 | 12002010202110002012211 |
4 | 301132310312130121 |
5 | 1332302403122340 |
6 | 40224031235121 |
7 | 3560423654140 |
oct | 613664663431 |
9 | 162122402184 |
10 | 53130520345 |
11 | 20594880351 |
12 | a369378aa1 |
13 | 50194c2826 |
14 | 28003d0757 |
15 | 15ae61b5ea |
hex | c5ed36719 |
53130520345 has 8 divisors (see below), whose sum is σ = 72864713664. Its totient is φ = 36432356784.
The previous prime is 53130520337. The next prime is 53130520349. The reversal of 53130520345 is 54302503135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53130520345 - 23 = 53130520337 is a prime.
It is a super-3 number, since 3×531305203453 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53130520349) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 759007399 + ... + 759007468.
It is an arithmetic number, because the mean of its divisors is an integer number (9108089208).
Almost surely, 253130520345 is an apocalyptic number.
It is an amenable number.
53130520345 is a deficient number, since it is larger than the sum of its proper divisors (19734193319).
53130520345 is a wasteful number, since it uses less digits than its factorization.
53130520345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1518014879.
The product of its (nonzero) digits is 27000, while the sum is 31.
The spelling of 53130520345 in words is "fifty-three billion, one hundred thirty million, five hundred twenty thousand, three hundred forty-five".
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