53131404340241 has 4 divisors (see below), whose sum is σ = 53131835294832. Its totient is φ = 53130973385652.

The previous prime is 53131404340237. The next prime is 53131404340253. The reversal of 53131404340241 is 14204340413135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53131404340241 - 2² = 53131404340237 is a prime.

It is a super-2 number, since 2×53131404340241² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53131404340211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215292311 + ... + 215538956.

It is an arithmetic number, because the mean of its divisors is an integer number (13282958823708).

Almost surely, 2^{53131404340241} is an apocalyptic number.

It is an amenable number.

53131404340241 is a deficient number, since it is larger than the sum of its proper divisors (430954591).

53131404340241 is a wasteful number, since it uses less digits than its factorization.

53131404340241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 430954590.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 53131404340241 its reverse (14204340413135), we get a palindrome (67335744753376).

The spelling of 53131404340241 in words is "fifty-three trillion, one hundred thirty-one billion, four hundred four million, three hundred forty thousand, two hundred forty-one".