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531314544443 = 3117139178853
BaseRepresentation
bin1111011101101001101…
…00001000111100111011
31212210102020001101120212
413232310310020330323
532201113010410233
61044025454341335
753246320053314
oct7566464107473
91783366041525
10531314544443
111953692331a1
1286b801ba84b
133b144971007
141ba0409760b
15dc49d71a48
hex7bb4d08f3b

531314544443 has 4 divisors (see below), whose sum is σ = 548453723328. Its totient is φ = 514175365560.

The previous prime is 531314544433. The next prime is 531314544457. The reversal of 531314544443 is 344445413135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 531314544443 - 218 = 531314282299 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 531314544443.

It is not an unprimeable number, because it can be changed into a prime (531314544413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8569589396 + ... + 8569589457.

It is an arithmetic number, because the mean of its divisors is an integer number (137113430832).

Almost surely, 2531314544443 is an apocalyptic number.

531314544443 is a deficient number, since it is larger than the sum of its proper divisors (17139178885).

531314544443 is a wasteful number, since it uses less digits than its factorization.

531314544443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17139178884.

The product of its digits is 691200, while the sum is 41.

Adding to 531314544443 its reverse (344445413135), we get a palindrome (875759957578).

The spelling of 531314544443 in words is "five hundred thirty-one billion, three hundred fourteen million, five hundred forty-four thousand, four hundred forty-three".

Divisors: 1 31 17139178853 531314544443