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531321054043 = 1349183240021
BaseRepresentation
bin1111011101101010011…
…00111110001101011011
31212210102200022010002011
413232311030332031123
532201121142212133
61044030250050351
753246426304613
oct7566514761533
91783380263064
10531321054043
11195371979a2a
1286b824199b7
133b14610cc50
141ba04cada43
15dc4a70a6cd
hex7bb533e35b

531321054043 has 8 divisors (see below), whose sum is σ = 573357271536. Its totient is φ = 489451317600.

The previous prime is 531321054037. The next prime is 531321054109. The reversal of 531321054043 is 340450123135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 531321054043 - 233 = 522731119451 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 531321053996 and 531321054014.

It is not an unprimeable number, because it can be changed into a prime (531321004043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41613628 + ... + 41626393.

It is an arithmetic number, because the mean of its divisors is an integer number (71669658942).

Almost surely, 2531321054043 is an apocalyptic number.

531321054043 is a deficient number, since it is larger than the sum of its proper divisors (42036217493).

531321054043 is a wasteful number, since it uses less digits than its factorization.

531321054043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 83240525.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 531321054043 its reverse (340450123135), we get a palindrome (871771177178).

The spelling of 531321054043 in words is "five hundred thirty-one billion, three hundred twenty-one million, fifty-four thousand, forty-three".

Divisors: 1 13 491 6383 83240021 1082120273 40870850311 531321054043