Search a number
-
+
5313440001 = 32961074023
BaseRepresentation
bin1001111001011010…
…01010100100000001
3111201022011201102010
410330231022210001
541340220040001
62235125243133
7245446331502
oct47455124401
914638151363
105313440001
112287331131
1210435634a9
13668a83c4c
14385972ba9
1521171c8d6
hex13cb4a901

5313440001 has 8 divisors (see below), whose sum is σ = 7328882880. Its totient is φ = 3420145232.

The previous prime is 5313439969. The next prime is 5313440047. The reversal of 5313440001 is 1000443135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5313440001 - 25 = 5313439969 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5313440001.

It is not an unprimeable number, because it can be changed into a prime (5313440051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30536925 + ... + 30537098.

It is an arithmetic number, because the mean of its divisors is an integer number (916110360).

Almost surely, 25313440001 is an apocalyptic number.

It is an amenable number.

5313440001 is a deficient number, since it is larger than the sum of its proper divisors (2015442879).

5313440001 is a wasteful number, since it uses less digits than its factorization.

5313440001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61074055.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 5313440001 is about 72893.3467540077. The cubic root of 5313440001 is about 1744.9859196517.

Adding to 5313440001 its reverse (1000443135), we get a palindrome (6313883136).

The spelling of 5313440001 in words is "five billion, three hundred thirteen million, four hundred forty thousand, one".

Divisors: 1 3 29 87 61074023 183222069 1771146667 5313440001