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53134403 = 731244859
BaseRepresentation
bin1100101010110…
…0010001000011
310200222111200212
43022230101003
5102100300103
65134504335
71213430540
oct312542103
9120874625
1053134403
1127aa1733
12159650ab
13b014c9a
1470b1bc7
1549e87d8
hex32ac443

53134403 has 8 divisors (see below), whose sum is σ = 62684160. Its totient is φ = 44074440.

The previous prime is 53134391. The next prime is 53134423. The reversal of 53134403 is 30443135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53134403 - 214 = 53118019 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53134423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 122213 + ... + 122646.

It is an arithmetic number, because the mean of its divisors is an integer number (7835520).

Almost surely, 253134403 is an apocalyptic number.

53134403 is a deficient number, since it is larger than the sum of its proper divisors (9549757).

53134403 is a wasteful number, since it uses less digits than its factorization.

53134403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 244897.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 53134403 is about 7289.3348804949. The cubic root of 53134403 is about 375.9458269433.

Adding to 53134403 its reverse (30443135), we get a palindrome (83577538).

The spelling of 53134403 in words is "fifty-three million, one hundred thirty-four thousand, four hundred three".

Divisors: 1 7 31 217 244859 1714013 7590629 53134403